MySQL 2023-03-27

MySQL两个查询如何合并成一个结果详解

MySQL 查询合并

如果我们需要将两个select语句的结果作为一个整体显示出来，我们就需要用到union或者union all关键字。union(或称为联合)的作用是将多个结果合并在一起显示出来。

注意：两个列表中的字段要一样才可以合并(顺序也要一样)

满足条件：

1、两个select查询的列的数量必须相同；

2、每个列的数据类型需要相似；

1.先写两条select

第一条select：

SELECT
DATE_FORMAT(add_time, ‘%Y-%m-%d’) as ‘add_time’,
COUNT(add_time) as ‘reach_intention’
FROM
table1
where
## where 条件可以根据自己实际情况来定
DATE_FORMAT(add_time, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 1 month), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_time, ‘%Y-%m-%d’)

这是查询出来的结果

结果一

第二条select：

select
DATE_FORMAT(add_date, ‘%Y-%m-%d’) as ‘add_time’ ,
COUNT(add_date) as ‘post_release’
from
table2
where
## where 条件可以根据自己实际情况来定
DATE_FORMAT(add_date, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 1 month), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_date, ‘%Y-%m-%d’)

第二条select查询出来的结果

2.合并查询结果

先把两条select用union all连接起来

SELECT
DATE_FORMAT(add_time, ‘%Y-%m-%d’) as ‘add_time’, COUNT(add_time) as ‘reach_intention’ , ” as ‘post_release’
FROM
table1
where
DATE_FORMAT(add_time, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 30 day), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_time, ‘%Y-%m-%d’)
UNION ALL
select
DATE_FORMAT(add_date, ‘%Y-%m-%d’) as ‘add_time’ , ” as ‘reach_intention’ , COUNT(add_date) as ‘post_release’
from
table2
where
DATE_FORMAT(add_date, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 30 day), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_date, ‘%Y-%m-%d’)

在外层嵌套一个select

## 括号里面放用 union all 连接的select
select * from () test
## 这里要给表起个别名不然会报 Every derived table must have its own alias 每个派生表都必须有自己的别名

把union all 连接的select 放到括号里面去然后运行

select
*
from
(
SELECT
DATE_FORMAT(add_time, ‘%Y-%m-%d’) as ‘add_time’, COUNT(add_time) as ‘reach_intention’ , ” as ‘post_release’
FROM
table1
where
DATE_FORMAT(add_time, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 30 day), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_time, ‘%Y-%m-%d’)
UNION ALL
select
DATE_FORMAT(add_date, ‘%Y-%m-%d’) as ‘add_time’ , ” as ‘reach_intention’ , COUNT(add_date) as ‘post_release’
from
table2
where
DATE_FORMAT(add_date, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 30 day), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_date, ‘%Y-%m-%d’)
) test

运行结果

把结果按日期分组排序。

使用 group by 和 order by 关键字

select
add_time,
sum(reach_intention) as ‘reach_intention’ ,
sum(post_release) as ‘post_release’
from
(
SELECT
DATE_FORMAT(add_time, ‘%Y-%m-%d’) as ‘add_time’, COUNT(add_time) as ‘reach_intention’ , ” as ‘post_release’
FROM
table1
where
DATE_FORMAT(add_time, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 30 day), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_time, ‘%Y-%m-%d’)
UNION ALL
select
DATE_FORMAT(add_date, ‘%Y-%m-%d’) as ‘add_time’ , ” as ‘reach_intention’ , COUNT(add_date) as ‘post_release’
from
table2
where
DATE_FORMAT(add_date, ‘%Y-%m-%d’) > DATE_FORMAT(date_sub(now(), interval 30 day), ‘%Y-%m-%d’)
group by
DATE_FORMAT(add_date, ‘%Y-%m-%d’) ) test
group by
test.add_time
order by
test.add_time desc

结果如下

总结

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MySQL 查询合并

1.先写两条select

2.合并查询结果

总结

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